bonjour à tous!
voici mon script:
$query = "SELECT distinct nfa_a FROM archive WHERE nfa_a LIKE \"%$Mot%\" ";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
$Nombre = $row[0];
if ($Nombre == "0") {
echo "<h2>Aucun résultat ne correspond à votre recherche</h2><p>";}
else {
$query = "SELECT distinct nfa_a FROM archive WHERE nfa_a LIKE \"%$Mot%\" ";
$result = mysql_query($query);
if ($Nombre == "1") {
echo "<a name=\"#resultat\"><h2>Résultat: </h2></a><p>";}
else {}
while($row = mysql_fetch_row($result)){
...
et j'ai l'erreur suivante:
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in d:\easyphp1-7\www\liste.php on line 62
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in d:\easyphp1-7\www\liste.php on line 92
aidez moi svp!